On or linked-to by the Website infringes your copyright, you should consider first contacting an attorney. ![]() Thus, if you are not sure content located Misrepresent that a product or activity is infringing your copyrights. Please be advised that you will be liable for damages (including costs and attorneys’ fees) if you materially Your Infringement Notice may be forwarded to the party that made the content available or to third parties such Means of the most recent email address, if any, provided by such party to Varsity Tutors. Infringement Notice, it will make a good faith attempt to contact the party that made such content available by If Varsity Tutors takes action in response to Information described below to the designated agent listed below. Or more of your copyrights, please notify us by providing a written notice (“Infringement Notice”) containing If you believe that content available by means of the Website (as defined in our Terms of Service) infringes one We can now substitute in our variables and solve for the missing piece. We can now substitute this equation into our work each to determine the work applied to the car. We know that our force applied must balance both of these forces. In this case the normal force is equal to the y component of the force of gravity. The force of friction is directly related to μ (the coefficient of friction) times the normal force. We know that the force of gravity is equal to mg Using trigonometric functions we get that To determine the Force of Gravity in the x-direction, we must break the force of gravity into components and examine the side acting in the x-direction. The forces opposing motion are the force of friction and the x-component of the gravitational force. The force in the direction of motion is the force applied which is doing work on the object. Since the car is moving at a constant velocity, all forces must be balanced. ![]() Therefore the first thing to do in this problem is to determine the amount of force needed to push the car up the incline. The work done on the object is equal to the net force done on the object multiplied by the displacement through which the force acts.
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